protected void Page_Load(object sender, EventArgs e)
{
txtDepartmentQuery.Attributes.Add("onKeyUp", "GetKeyUp(event)");
}
Thursday, July 17, 2008
key press code
Key Pressed | Javascript Key Code |
backspace | 8 |
tab | 9 |
enter | 13 |
shift | 16 |
ctrl | 17 |
alt | 18 |
pause/break | 19 |
caps lock | 20 |
escape | 27 |
page up | 33 |
page down | 34 |
end | 35 |
home | 36 |
left arrow | 37 |
up arrow | 38 |
right arrow | 39 |
down arrow | 40 |
insert | 45 |
delete | 46 |
0 | 48 |
1 | 49 |
2 | 50 |
3 | 51 |
4 | 52 |
5 | 53 |
6 | 54 |
7 | 55 |
8 | 56 |
9 | 57 |
a | 65 |
b | 66 |
c | 67 |
d | 68 |
e | 69 |
f | 70 |
g | 71 |
h | 72 |
i | 73 |
j | 74 |
k | 75 |
l | 76 |
m | 77 |
n | 78 |
o | 79 |
p | 80 |
q | 81 |
r | 82 |
s | 83 |
t | 84 |
u | 85 |
v | 86 |
w | 87 |
x | 88 |
y | 89 |
z | 90 |
left window key | 91 |
right window key | 92 |
select key | 93 |
numpad 0 | 96 |
numpad 1 | 97 |
numpad 2 | 98 |
numpad 3 | 99 |
numpad 4 | 100 |
numpad 5 | 101 |
numpad 6 | 102 |
numpad 7 | 103 |
numpad 8 | 104 |
numpad 9 | 105 |
multiply | 106 |
add | 107 |
subtract | 109 |
decimal point | 110 |
divide | 111 |
f1 | 112 |
f2 | 113 |
f3 | 114 |
f4 | 115 |
f5 | 116 |
f6 | 117 |
f7 | 118 |
f8 | 119 |
f9 | 120 |
f10 | 121 |
f11 | 122 |
f12 | 123 |
num lock | 144 |
scroll lock | 145 |
semi-colon | 186 |
equal sign | 187 |
comma | 188 |
dash | 189 |
period | 190 |
forward slash | 191 |
grave accent | 192 |
open bracket | 219 |
back slash | 220 |
close braket | 221 |
single quote | 222 |
source: http://www.cambiaresearch.com/c4/702b8cd1-e5b0-42e6-83ac-25f0306e3e25/Javascript-Char-Codes-Key-Codes.aspx
Tuesday, July 15, 2008
Reset Table Identity column to 0
Source: http://geekswithblogs.net/TakeNote/archive/2007/11/30/117258.aspx
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This is one of those simple tip posts that may seem obvious and taken for granted by those of us who have been working with SQL Server for a while now but maybe a newbie or two out there will find this helpful.
=====
This is one of those simple tip posts that may seem obvious and taken for granted by those of us who have been working with SQL Server for a while now but maybe a newbie or two out there will find this helpful.
Every so often (just this morning!) I find myself resetting an identity column value back to 0 after I've deleted all the existing records so the table gets a fresh start at primary key 1. Yes, I know all about primary keys not changing and how the value in the primary key doesn't matter and so on. Sometimes I just like the primary keys starting at 1.
The following line resets the Identity value for the Customer table to 0 so that the next record added starts at 1.
DBCC CHECKIDENT('Customer', RESEED, 0)
Have a day. :-|
Friday, November 30, 2007 9:18 AM
===
Monday, July 14, 2008
"Cannot insert explicit value for identity column"
asp.net | 3.5 | c# | linq
I had an error "Cannot insert explicit value for identity column."
I had my primary column set to be an identity column. I didn't know how to trace my error because everything was correct. But, sometimes when table definition changed and may have created diagram before the column was designated to be the identity column an error occurs. In this case, you delete the table and readd the table on to your dbml/diagram [Linq to SQL Classes].
I had an error "Cannot insert explicit value for identity column."
I had my primary column set to be an identity column. I didn't know how to trace my error because everything was correct. But, sometimes when table definition changed and may have created diagram before the column was designated to be the identity column an error occurs. In this case, you delete the table and readd the table on to your dbml/diagram [Linq to SQL Classes].
Wednesday, July 2, 2008
Linq Distinct
Lets' say I have two tables. Here, you have SectionTable and SectionName.
On SectionTable you have duplicate value of of SectionID.
On SectionName, you have no duplicate values.
"from st in db.SectionTable select st" you will get the Grid Data of SectionTable
"from sn in db.SectionName select sn" you will get the Grid Data of SectionName.
How do you marry these two tables to get a Distinctive Values?
(from st in db.SectionTable
from sn in db.SectionName
where st.SectionID == sn.TableID
select new
{
SectionID = sn.TableID
SectionName = sn.SectionName
}).Distinct();
If you wrap ().Distinct() around your query, you get Distict value of the both!
Hope that Helps...
|
|
On SectionName, you have no duplicate values.
"from st in db.SectionTable select st" you will get the Grid Data of SectionTable
"from sn in db.SectionName select sn" you will get the Grid Data of SectionName.
How do you marry these two tables to get a Distinctive Values?
(from st in db.SectionTable
from sn in db.SectionName
where st.SectionID == sn.TableID
select new
{
SectionID = sn.TableID
SectionName = sn.SectionName
}).Distinct();
If you wrap ().Distinct() around your query, you get Distict value of the both!
Hope that Helps...
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